Aftab tells his daughter,"Seven years ago,$I$ was seven times as old as you were then. Also,three years from now,$I$ shall be three times as old as you will be." Represent this situation algebraically and graphically.

(N/A) Let the present age of Aftab be $x$ and the present age of his daughter be $y$.
Seven years ago:
Age of Aftab $= x - 7$
Age of his daughter $= y - 7$
According to the problem,$(x - 7) = 7(y - 7) \implies x - 7 = 7y - 49 \implies x - 7y = -42$ $...(1)$
Three years from now:
Age of Aftab $= x + 3$
Age of his daughter $= y + 3$
According to the problem,$(x + 3) = 3(y + 3) \implies x + 3 = 3y + 9 \implies x - 3y = 6$ $...(2)$
Algebraic representation:
$x - 7y = -42$
$x - 3y = 6$
For $x - 7y = -42$,we have $x = 7y - 42$:

$x$	$-7$	$0$	$7$
$y$	$5$	$6$	$7$

For $x - 3y = 6$,we have $x = 3y + 6$:

$x$	$6$	$3$	$0$
$y$	$0$	$-1$	$-2$